A square surface 3 m x 3 m lies in a vertical line in water pipe its upper edge at vater surface. The hydrostatic force on square surface is A. 9,000 kg B. 13,500 kg C. 18,000 kg D. 27,000 kg

[amp_mcq option1=”9,000 kg” option2=”13,500 kg” option3=”18,000 kg” option4=”27,000 kg” correct=”option3″]

The correct answer is $\boxed{\text{D}}$.

The hydrostatic force on a surface is given by the following equation:

$$F = \rho g h A$$

where:

  • $\rho$ is the density of the fluid,
  • $g$ is the acceleration due to gravity,
  • $h$ is the depth of the surface, and
  • $A$ is the area of the surface.

In this case, we are given that the density of water is $\rho = 1000 \frac{kg}{m^3}$, the acceleration due to gravity is $g = 9.8 \frac{m}{s^2}$, the depth of the surface is $h = 3 m$, and the area of the surface is $A = 3 m \times 3 m = 9 m^2$. Substituting these values into the equation for the hydrostatic force, we get:

$$F = (1000 \frac{kg}{m^3})(9.8 \frac{m}{s^2})(3 m)(9 m^2) = 27,000 \text{ N}$$

Therefore, the hydrostatic force on the square surface is $\boxed{27,000 \text{ N}}$.

Option A is incorrect because it is the force on a square surface with an area of $1 m^2$. Option B is incorrect because it is the force on a square surface with an area of $2 m^2$. Option C is incorrect because it is the force on a square surface with an area of $4 m^2$.

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