A point on a curve is said to be an extremum if it is a local minimum or a local maximum. The number of distinct extrema for the curve 3×4 – 16×3 – 24×2 + 37 is A. 0 B. 1 C. 2 D. 3

0
1
2
3

The correct answer is $\boxed{\text{C}}$.

To find the number of distinct extrema for a curve, we can use the following steps:

  1. Find the critical points of 512"> Subscribe on YouTube
the curve. These are the points where the derivative of the curve is equal to zero.
  • Evaluate the derivative of the curve at each critical point. If the derivative is positive at a critical point, then the curve has a local minimum at that point. If the derivative is negative at a critical point, then the curve has a local maximum at that point.
  • If the derivative changes sign between two critical points, then there must be an extremum between those points.
  • In this case, the derivative of the curve is $12x(x-1)(x-2)$. The critical points are $x=0$, $x=1$, and $x=2$. The derivative is positive at $x=0$ and $x=2$, and negative at $x=1$. Therefore, the curve has a local minimum at $x=0$ and a local maximum at $x=2$. There is no extremum between $x=0$ and $x=1$, or between $x=1$ and $x=2$. Therefore, there are $\boxed{2}$ distinct extrema for the curve.