A point on a curve is said to be an extremum if it is a local minimum or a local maximum. The number of distinct extrema for the curve 3×4 – 16×3 – 24×2 + 37 is A. 0 B. 1 C. 2 D. 3

The correct answer is $\boxed{\text{C}}$.

To find the number of distinct extrema for a curve, we can use the following steps:

1. Find the critical points of the curve. These are the points where the derivative of the curve is equal to zero.
2. Evaluate the derivative of the curve at each critical point. If the derivative is positive at a critical point, then the curve has a local minimum at that point. If the derivative is negative at a critical point, then the curve has a local maximum at that point.
3. If the derivative changes sign between two critical points, then there must be an extremum between those points.

In this case, the derivative of the curve is $12x(x-1)(x-2)$. The critical points are $x=0$, $x=1$, and $x=2$. The derivative is positive at $x=0$ and $x=2$, and negative at $x=1$. Therefore, the curve has a local minimum at $x=0$ and a local maximum at $x=2$. There is no extremum between $x=0$ and $x=1$, or between $x=1$ and $x=2$. Therefore, there are $\boxed{2}$ distinct extrema for the curve.