A piece of metal of specific gravity 13.6 is placed in mercury of specific gravity 13.6, what fraction of it volume is under mercury? A. the metal piece will simply float over the mercury B. the metal piece will be immersed in mercury by half C. whole of the metal piece will be immersed with its top surface just at mercury level D. metal piece will sink to the bottom

[amp_mcq option1=”the metal piece will simply float over the mercury” option2=”the metal piece will be immersed in mercury by half” option3=”whole of the metal piece will be immersed with its top surface just at mercury level” option4=”metal piece will sink to the bottom” correct=”option4″]

The correct answer is D.

Specific gravity is a dimensionless number that compares the density of a substance to the density of a standard substance. The standard substance for specific gravity is water, which has a specific gravity of 1.0.

A piece of metal with a specific gravity of 13.6 is more dense than mercury, which has a specific gravity of 13.6. Therefore, the metal piece will sink to the bottom of the mercury.

Option A is incorrect because the metal piece will not float over the mercury. The metal piece is more dense than the mercury, so it will sink.

Option B is incorrect because the metal piece will not be immersed in mercury by half. The metal piece will sink to the bottom of the mercury.

Option C is incorrect because the metal piece will not be immersed with its top surface just at mercury level. The metal piece will sink to the bottom of the mercury.

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