A piece of ice, 100 g in mass is kept at 0 °C. The amount of heat it requires to melt at 0 °C is (take latent heat of melting of ice to be 333.6 J/g):
[amp_mcq option1=”750.6 J” option2=”83.4 J” option3=”33360 J” option4=”3.336 J” correct=”option3″]
This question was previously asked in
UPSC CDS-1 – 2016
– Given mass of ice m = 100 g.
– Given latent heat of melting of ice L = 333.6 J/g.
– Heat required Q = 100 g * 333.6 J/g = 33360 J.