The correct answer is: $\boxed{\text{C. }[S] \text{ is skew-symmetric and }[D] \text{ is symmetric}}$.
A square matrix $A$ is symmetric if $A^T = A$, and it is skew-symmetric if $A^T = -A$.
We are given that $A$ is neither symmetric nor skew-symmetric. This means that $A^T \neq A$ and $A^T \neq -A$.
The sum of two symmetric matrices is always symmetric. The sum of two skew-symmetric matrices is always skew-symmetric. The difference of a symmetric matrix and a skew-symmetric matrix is always skew-symmetric.
Therefore, $[S] = [A] + [A]^T$ is skew-symmetric, and $[D] = [A] – [A]^T$ is symmetric.