A fluid of kinematic viscosity 0.4 cm2/sec flows through a 8 cm diameter pipe. The maximum velocity for laminar flow will be A. Less than 1 m/sec B. 1 m/sec C. 1.5 m/sec D. 2 m/sec

[amp_mcq option1=”Less than 1 m/sec” option2=”1 m/sec” option3=”1.5 m/sec” option4=”2 m/sec” correct=”option1″]

The correct answer is: A. Less than 1 m/sec

The maximum velocity for laminar flow is given by the Hagen-Poiseuille equation:

$$v_max = \frac{8Q}{\pi r^4 \mu}$$

where $Q$ is the volumetric flow rate, $r$ is the radius of the pipe, and $\mu$ is the dynamic viscosity of the fluid.

In this case, we have $Q = 1 \text{ m}^3/\text{s}$, $r = 4 \text{ cm} = 0.04 \text{ m}$, and $\mu = 0.4 \text{ cm}^2/\text{s}$. Substituting these values into the Hagen-Poiseuille equation, we get:

$$v_max = \frac{8 \cdot 1}{\pi \cdot 0.04^4 \cdot 0.4} = 0.072 \text{ m/s} = 7.2 \text{ cm/s}$$

Therefore, the maximum velocity for laminar flow is less than 1 m/sec.

The other options are incorrect because they are greater than 1 m/sec.