A circuit has two different voltage sources that are connected in a series-aiding form. If the sources are rated at 6 V and 9 V, what is the total source voltage? A. 15 V B. 16 V C. 7.5 V D. 8 V E. None of the above

[amp_mcq option1=”15 V” option2=”16 V” option3=”7.5 V” option4=”8 V E. None of the above” correct=”option3″]

The correct answer is $\boxed{\text{A}}$.

When two voltage sources are connected in series-aiding form, the total voltage is the sum of the individual voltages. In this case, the total voltage is $6 V + 9 V = 15 V$.

Option B is incorrect because it is the sum of the two voltages plus 1 volt. Option C is incorrect because it is the average of the two voltages. Option D is incorrect because it is the difference of the two voltages. Option E is incorrect because it is not a valid option.