A walks 10 metres in front and 10 metres to the right. Then every time

A walks 10 metres in front and 10 metres to the right. Then every time turning to his left he walks 5, 15 and 15 metres respectively. How far is he now from his starting point ?

55 metres
23 metres
5 metres
None of these
This question was previously asked in
UPSC CAPF – 2019
The person is 5 metres away from their starting point.
The problem can be solved by tracking the person’s displacement in two perpendicular directions (e.g., North-South and East-West).
Assume ‘front’ is North.
1. 10 metres in front (North): Displacement (0, +10)
2. 10 metres to the right (East from the North direction): Displacement (+10, 0)
Total displacement so far: (+10, +10) from start. Current position is (10, 10) relative to start (0, 0). Direction is East.
3. Turning left (now facing North) walks 5 metres: Displacement (0, +5).
Total displacement: (+10, +10) + (0, +5) = (+10, +15). Current position (10, 15). Direction is North.
4. Turning left (now facing West) walks 15 metres: Displacement (-15, 0).
Total displacement: (+10, +15) + (-15, 0) = (-5, +15). Current position (-5, 15). Direction is West.
5. Turning left (now facing South) walks 15 metres: Displacement (0, -15).
Total displacement: (-5, +15) + (0, -15) = (-5, 0). Current position (-5, 0).
The starting point is (0, 0). The final position is (-5, 0).
The distance from the starting point is the straight-line distance between (0, 0) and (-5, 0), which is 5 metres.