If A is coded as 1, B as 3, C as 5 and so on, which of the following is the numerical value of the word ‘FAZED’ if the numerical value of ‘CABLE’ is 41?
Position of A = 1. Code = 1*2 – 1 = 1.
Position of B = 2. Code = 2*2 – 1 = 3.
Position of C = 3. Code = 3*2 – 1 = 5.
The rule is: Code = (Letter Position) * 2 – 1.
The numerical value of a word is the sum of the numerical values (codes) of its letters.
Let’s verify the value for ‘CABLE’ = 41 using the rule:
C = 3rd letter -> 3*2 – 1 = 5
A = 1st letter -> 1*2 – 1 = 1
B = 2nd letter -> 2*2 – 1 = 3
L = 12th letter -> 12*2 – 1 = 23
E = 5th letter -> 5*2 – 1 = 9
Sum = 5 + 1 + 3 + 23 + 9 = 41. The rule is correct.
Now, find the numerical value of ‘FAZED’:
F = 6th letter -> 6*2 – 1 = 11
A = 1st letter -> 1*2 – 1 = 1
Z = 26th letter -> 26*2 – 1 = 51
E = 5th letter -> 5*2 – 1 = 9
D = 4th letter -> 4*2 – 1 = 7
Sum = 11 + 1 + 51 + 9 + 7 = 79.
The numerical value of ‘FAZED’ is 79.