The width of a rectangle is 4x which is only 25% of its length. What are the area and the perimeter of the rectangle respectively ?
16x² squnit and 16x unit
20x² squnit and 40x unit
32x² squnit and 64x unit
64x² squnit and 40x unit
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC CAPF – 2009
We are given the width: w = 4x.
We are told that the width is 25% of its length.
w = 25% of l
w = 0.25 * l
Substitute the value of w:
4x = 0.25 * l
To find the length l, divide by 0.25:
l = 4x / 0.25
l = 4x / (1/4)
l = 4x * 4
l = 16x
So, the length of the rectangle is 16x and the width is 4x.
Area of the rectangle = length * width
Area = l * w = (16x) * (4x) = 16 * 4 * x * x = 64x² sq units.
Perimeter of the rectangle = 2 * (length + width)
Perimeter = 2 * (l + w) = 2 * (16x + 4x) = 2 * (20x) = 40x units.
The area is 64x² sq units and the perimeter is 40x units.