In a solenoid, the current flowing through the wire is I and number of turns per unit length is n. This gives a magnetic field B inside the solenoid. If number of turn per unit length is increased to 2n, what will be the value of magnetic field in the solenoid?
B
2B
B/2
B/4
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC NDA-1 – 2017
The formula for the magnetic field inside an ideal long solenoid is B = μ₀ * n * I, where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current. If the number of turns per unit length is increased to 2n while the current I remains the same, the new magnetic field B’ will be B’ = μ₀ * (2n) * I = 2 * (μ₀ * n * I).