Consider metallic spheres of different radii r, all at the same electrostatic potential. Then the magnitude E of the electric field just outside these spheres depends on r as :
E ∝ r<sup>-2</sup>
E ∝ r<sup>-1</sup>
E ∝ r<sup>0</sup>
E ∝ r
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UPSC Geoscientist – 2024
For a metallic sphere (conductor), the charge resides on its surface. The electrostatic potential V at the surface of a conducting sphere of radius r with charge Q is given by V = Q / (4πε₀r). The electric field E just outside the surface is given by E = Q / (4πε₀r²).
Given that all spheres are at the same electrostatic potential V, we can express the charge Q in terms of V and r: Q = V * (4πε₀r). Substitute this expression for Q into the formula for E.