A bus starting from a bus-stand and moving with uniform acceleration a

A bus starting from a bus-stand and moving with uniform acceleration attains a speed of 20 km/h in 10 minutes. What is its acceleration?

200 km/h<sup>2</sup>
120 km/h<sup>2</sup>
100 km/h<sup>2</sup>
240 km/h<sup>2</sup>
This question was previously asked in
UPSC CDS-2 – 2021
The bus starts from rest, so its initial velocity (u) is 0 km/h. Its final velocity (v) is 20 km/h, attained in time (t) = 10 minutes. To find acceleration (a) in km/h², we need to convert time to hours: 10 minutes = 10/60 hours = 1/6 hours. Using the equation of motion v = u + at, we get 20 km/h = 0 km/h + a × (1/6) hours. Solving for a: a = 20 × 6 = 120 km/h².
Acceleration is the rate of change of velocity (a = (v-u)/t). Ensure that all units are consistent before performing calculations. If velocity is in km/h and time in hours, acceleration will be in km/h².
The problem specifies uniform acceleration, allowing the use of standard kinematic equations. Other equations of motion like s = ut + ½at² and v² = u² + 2as can also be used depending on the given and required variables.