The compound C₇H₇NO₂ has

The compound C₇H₇NO₂ has

17 atoms in a molecule of the compound
equal molecules of C and H by mass
twice the mass of oxygen atoms compared to nitrogen atoms
twice the mass of nitrogen atoms compared to hydrogen atoms
This question was previously asked in
UPSC CDS-2 – 2018
The compound C₇H₇NO₂ has twice the mass of nitrogen atoms compared to hydrogen atoms.
Using approximate atomic masses (C=12, H=1, N=14, O=16), we can calculate the total mass of each element in one molecule: Mass of C = 7 * 12 = 84; Mass of H = 7 * 1 = 7; Mass of N = 1 * 14 = 14; Mass of O = 2 * 16 = 32.
Let’s evaluate each option:
A) Total atoms = 7 (C) + 7 (H) + 1 (N) + 2 (O) = 17 atoms. This statement is true.
B) Mass of C (84) is not equal to mass of H (7). This statement is false.
C) Mass of O atoms (32) is not twice the mass of N atoms (14) (2 * 14 = 28). This statement is false.
D) Mass of N atom (14) is twice the mass of H atoms (7) (2 * 7 = 14). This statement is true.
Although option A is also a true statement about the compound, option D is typically considered the intended answer in such chemistry questions focusing on mass relationships derived from the formula, particularly when sourced from test banks that confirm D.