The number of moles of oxygen gas used in the complete combustion of 1

The number of moles of oxygen gas used in the complete combustion of 1 mole of glucose is :

[amp_mcq option1=”1″ option2=”3″ option3=”6″ option4=”12″ correct=”option3″]

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UPSC CDS-1 – 2022

The balanced chemical equation for the complete combustion of glucose (C6H12O6) shows that 1 mole of glucose reacts with 6 moles of oxygen gas (O2).

Complete combustion of a hydrocarbon or carbohydrate involves reaction with sufficient oxygen to produce carbon dioxide (CO2) and water (H2O). Balancing the chemical equation ensures that the number of atoms of each element is the same on both the reactant and product sides, representing the stoichiometric ratios.

The balanced combustion reaction for glucose is: C6H12O6(s) + 6O2(g) -> 6CO2(g) + 6H2O(l). From this equation, the molar ratio of glucose to oxygen is 1:6. Therefore, 1 mole of glucose requires 6 moles of oxygen gas for complete combustion.

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