The pressure in Pascals at a depth of 1 m below the free surface of a body of water will be equal to A. 1 Pa B. 91 Pa C. 981 Pa D. 9810 Pa

The correct answer is C. 981 Pa.

The pressure at a depth of 1 m below the free surface of a body of water is equal to the weight of the water column above it. The density of water is 1000 kg/m3, and the acceleration due to gravity is 9.8 m/s2. Therefore, the pressure is:

$P = \rho g h = 1000 \frac{kg}{m^3} \times 9.8 \frac{m}{s^2} \times 1 m = 981 Pa$

Option A is incorrect because it is the pressure at a depth of 1 cm below the free surface of water. Option B is incorrect because it is the pressure at a depth of 10 cm below the free surface of water. Option D is incorrect because it is the pressure at a depth of 100 cm below the free surface of water.