A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is A. 40 sec B. 30 sec C. 20 sec D. 15 sec

40 sec
30 sec
20 sec
15 sec

The correct answer is C. 20 sec.

The equation for the distance traveled by an object with a constant acceleration is $d = v_0 t + \frac{1}{2} at^2$, where $v_0$ is the initial velocity, $t$ is the time, and $a$ is the acceleration. We are given that $v_0 = 2 \text{ m/s}$, $a = -0.1 \text{ m/s}^2$, and $d = 1.5 \text{ m}$. Substituting these values into the equation, we get $1.5 = 2 t + \frac{1}{2} (-0.1) t^2$. Solving for $t$, we get $t = 20 \text{ sec}$.

Option A is incorrect because it is twice the correct answer. Option B is incorrect because it is three times the correct answer. Option D is incorrect because it is half the correct answer.