The correct answer is C. 50 m.
The total distance traveled by a particle is the integral of its speed over time. The speed of a particle is the rate of change of its position, which is given by the derivative of its position with respect to time. In this case, the position of the particle is given by the equation $x = t^2 – 10t + 30$, so the speed is given by $v = \frac{d}{dt} x = 2t – 10$.
To find the total distance traveled by the particle from $t = 0$ to $t = 10$, we need to integrate the speed from $t = 0$ to $t = 10$. This gives us
$$\int_0^{10} v(t) dt = \int_0^{10} (2t – 10) dt = t^2 – 5t + 30|_0^{10} = 100 – 50 + 30 = 50.$$
Therefore, the total distance traveled by the particle from $t = 0$ to $t = 10$ is 50 meters.
Option A is incorrect because the particle is moving at all times, so it must have traveled some distance. Option B is incorrect because the particle is moving in a positive direction, so it cannot have traveled a negative distance. Option D is incorrect because the particle is moving in a positive direction, so it cannot have traveled a distance of 60 meters.