If depth of slab is 10 cm, width of web 30 cm, depth of web 50 cm, centre to centre distance of beams 3 m, effective span of beams 6 m, the effective flange width of the beam, is A. 200 cm B. 300 cm C. 150 cm D. 100 cm

[amp_mcq option1=”200 cm” option2=”300 cm” option3=”150 cm” option4=”100 cm” correct=”option3″]

The correct answer is C. 150 cm.

The effective flange width of a beam is the width of the flange that is effective in resisting bending moment. It is calculated as follows:

$b_e = \frac{b_f}{2} + \frac{d_w}{2}$

where:

  • $b_e$ is the effective flange width
  • $b_f$ is the flange width
  • $d_w$ is the web depth

In this case, we have:

  • $b_f = 30$ cm
  • $d_w = 50$ cm

Therefore, the effective flange width is:

$b_e = \frac{30}{2} + \frac{50}{2} = 150$ cm

The other options are incorrect because they do not take into account the width of the web.