The correct answer is A. 2.75 cm.
The eccentricity (e) of a hollow circular column is given by the following equation:
$$e = \frac{r_o^2 – r_i^2}{2}$$
where $r_o$ is the outer radius of the column and $r_i$ is the inner radius of the column.
In this case, $r_o = 25\text{ cm}$ and $r_i = 15\text{ cm}$. Substituting these values into the equation, we get:
$$e = \frac{(25\text{ cm})^2 – (15\text{ cm})^2}{2} = 2.75\text{ cm}$$
Therefore, the eccentricity of the hollow circular column is 2.75 cm.
The other options are incorrect because they do not represent the correct value of the eccentricity.