The eccentricity (e) of a hollow circular column, external diameter 25 cm, internal diameter 15 cm for an eccentric load 100 t for non-development of tension, is A. 2.75 cm B. 3.00 cm C. 3.50 cm D. 4.25 cm

2.75 cm
3.00 cm
3.50 cm
4.25 cm

The correct answer is A. 2.75 cm.

The eccentricity (e) of a hollow circular column is given by the following equation:

$$e = \frac{r_o^2 – r_i^2}{2}$$

where $r_o$ is the outer radius of the column and $r_i$ is the inner radius of the column.

In this case, $r_o = 25\text{ cm}$ and $r_i = 15\text{ cm}$. Substituting these values into the equation, we get:

$$e = \frac{(25\text{ cm})^2 – (15\text{ cm})^2}{2} = 2.75\text{ cm}$$

Therefore, the eccentricity of the hollow circular column is 2.75 cm.

The other options are incorrect because they do not represent the correct value of the eccentricity.