In Traditional Approach, which one is correct?

kc rises constantly
kd decreases constantly
k0 decreases constantly
None of the above

The correct answer is: D. None of the above

In the traditional approach, the rate of a chemical reaction is given by the following equation:

$$r = k[A]^x[B]^y$$

where $k$ is the rate constant, $[A]$ is the concentration of reactant A, $[B]$ is the concentration of reactant B, and $x$ and $y$ are the orders of the reaction with respect to A and B, respectively.

The rate constant $k$ is a measure of the rate at which the reaction proceeds. It is a constant for a given reaction at a given temperature, but it can vary with temperature.

The orders of the reaction, $x$ and $y$, are determined experimentally. They can be integers or fractions.

If the rate of the reaction is proportional to the square of the concentration of reactant A, then $x = 2$. If the rate of the reaction is proportional to the concentration of reactant A and the square of the concentration of reactant B, then $x = 1$ and $y = 2$.

In the traditional approach, it is assumed that the rate constant $k$ is constant. However, this is not always the case. The rate constant can vary with temperature, pressure, and the presence of catalysts.

In the traditional approach, it is also assumed that the orders of the reaction, $x$ and $y$, are constant. However, this is not always the case. The orders of the reaction can change with temperature, pressure, and the presence of catalysts.

Therefore, the correct answer to the question “In Traditional Approach, which one is correct?” is D. None of the above.