[amp_mcq option1=”118″ option2=”120″ option3=”121″ option4=”119″ correct=”option1″]
The correct answer is (a) 118.
There are 100 numbers from 101 to 200. In each of the numbers from 101 to 199, the digit 1 appears once. In the number 200, the digit 1 appears twice. Therefore, the digit 1 appears a total of 100 + 1 – 1 = 118 times.
Option (b) is incorrect because it counts the digit 1 twice in the number 200. Option (c) is incorrect because it counts the digit 1 three times in the number 200. Option (d) is incorrect because it counts the digit 1 four times in the number 200.