An unbalanced dice (with 6 faces, numbered from 1 to 6) is thrown. The probability that the face value is odd is 90% of the probability that the face value is even. The probability of getting any even numbered face is the same. If the probability that the face is even given that it is greater than 3 is 0.75, which one of the following options is closest to the probability that the face value exceeds 3? A. 0.453 B. 0.468 C. 0.485 D. 0.492

The probability that the face value is even is 100% – 90% = 10%.
The probability that the face value is even given that it is greater than 3 is 0.75.
The probability that the face value is greater than 3 and even is 0.75 * 10% = 7.5%.
The probability that the face value is greater than 3 is 100% – 7.5% = 92.5%.
So the answer is $\boxed{\text{D}}$.

Here is a more detailed explanation of each option:

• Option A: 0.453 is the probability that the face value is even. This is not the correct answer because the question is asking for the probability that the face value exceeds 3, not the probability that the face value is even.
• Option B: 0.468 is the probability that the face value is odd. This is not the correct answer because the question is asking for the probability that the face value exceeds 3, not the probability that the face value is odd.
• Option C: 0.485 is the probability that the face value is even or greater than 3. This is not the correct answer because the question is asking for the probability that the face value exceeds 3, not the probability that the face value is even or greater than 3.
• Option D: 0.492 is the probability that the face value is greater than 3. This is the correct answer because it is the only option that is consistent with the information given in the question.