Consider function f(x) = (x2 – 4)2 where x is a real number. Then the function has A. only one minimum B. only two minima C. three minima D. three maxima

only one minimum
only two minima
three minima
three maxima

The correct answer is A. only one minimum.

The function $f(x) = (x^2 – 4)^2$ is a parabola with its vertex at $x=2$. The parabola opens upwards, so it has only one minimum point, which is at $x=2$.

The other options are incorrect because they state that the function has more than one minimum point.