The angle between two unit-magnitude coplanar vectors P(0.866, 0.500, 0) and Q(0.259, 0.966, 0) will be A. 0° B. 30° C. 45° D. 60°

0°
30°
45°
60°

The correct answer is $\boxed{\text{B}}$.

The angle between two vectors can be calculated using the following formula:

$$\cos \theta = \frac{\mathbf{u} \cdot \mathbf{v}}{|\mathbf{u}||\mathbf{v}|}$$

where $\mathbf{u}$ and $\mathbf{v}$ are the two vectors, and $\theta$ is the angle between them.

In this case, the vectors are $\mathbf{u} = (0.866, 0.500, 0)$ and $\mathbf{v} = (0.259, 0.966, 0)$. Substituting these values into the formula, we get:

$$\cos \theta = \frac{(0.866)(0.259) + (0.500)(0.966) + (0)(0)}{|(0.866, 0.500, 0)| |(0.259, 0.966, 0)|} = 0.7071067811865475$$

Taking the arccosine of both sides, we get:

$$\theta = \arccos 0.7071067811865475 = 45^\circ$$

Therefore, the angle between the two vectors is $\boxed{45^\circ}$.

The other options are incorrect because they do not correspond to the angle between the two vectors.