The rank of the matrix \[{\text{M}} = \left[ {\begin{array}{*{20}{c}} 5&{10}&{10} \\ 1&0&2 \\ 3&6&6 \end{array}} \right]\] is A. 0 B. 1 C. 2 D. 3

0
1
2
3

The rank of a matrix is the number of linearly independent rows or columns in the matrix. To find the rank of a matrix, we can use Gaussian elimination.

In Gaussian elimination, we reduce the matrix to row echelon form. A row echelon form is a matrix in which all the rows below the main diagonal are zero, and the leading coefficient of each non-zero row is 1.

To reduce the matrix to row echelon form, we can use the following operations:

  • Add or subtract a multiple of one row to another row.
  • Multiply a row by a non-zero constant.
  • Swap two rows.

Once the matrix is in row echelon form, the rank is the number of non-zero rows in the matrix.

For the matrix $M$, we can reduce it to row echelon form as follows:

[{\text{M}} = \left[ {\begin{array}{*{20}{c}} 5&{10}&{10} \ 1&0&2 \ 3&6&6 \end{array}} \right]]

Subtract 3 rows of the first row from the third row, we get

[{\text{M}} = \left[ {\begin{array}{*{20}{c}} 5&{10}&{10} \ 1&0&2 \ 0&6&-6 \end{array}} \right]]

Swap the second row with the first row, we get

[{\text{M}} = \left[ {\begin{array}{*{20}{c}} 1&0&2 \ 0&6&-6 \end{array}} \right]]

Divide the second row by 6, we get

[{\text{M}} = \left[ {\begin{array}{*{20}{c}} 1&0&2 \ 0&1&-1 \end{array}} \right]]

Since there are two non-zero rows in the row echelon form of the matrix, the rank of the matrix is 2.

Therefore, the correct answer is $\boxed{\text{C}}$.