What is the phase shift between total current and voltage, if 100 ohm resistor connected in parallel with an inductor that has a reactance of 200W? A. 0 degree B. 26.6 degree C. 90 degree D. 180 degree E. None of the above

The correct answer is $\boxed{\text{B. 26.6 degree}}$.

In a parallel RLC circuit, the phase angle between the current and voltage is given by:

$$\phi = \arctan \left(\frac{X_L}{R}\right)$$

where $X_L$ is the inductive reactance and $R$ is the resistance.

In this case, we are given that $R = 100 \Omega$ and $X_L = 200 \Omega$. Substituting these values into the equation, we get:

$$\phi = \arctan \left(\frac{200 \Omega}{100 \Omega}\right) = 26.6^\circ$$

Therefore, the phase shift between the total current and voltage is 26.6 degrees.

Option A is incorrect because it is the phase angle between the current and voltage in a purely resistive circuit. In a purely resistive circuit, there is no inductive reactance, so the phase angle is 0 degrees.

Option C is incorrect because it is the phase angle between the current and voltage in a purely inductive circuit. In a purely inductive circuit, there is no resistive component, so the phase angle is 90 degrees.

Option D is incorrect because it is the phase angle between the current and voltage in a purely capacitive circuit. In a purely