A power transformer steps 100 V down to 10 V. If the current in its primary winding is 2 A, what is the current in the secondary winding? A. 50 A B. 12:00 AM C. 5:00 AM D. 20 A E. None of the above

[amp_mcq option1=”50 A” option2=”12:00 AM” option3=”5:00 AM” option4=”20 A E. None of the above” correct=”option3″]

The correct answer is $\boxed{\text{D}}$, 20 A.

The current in the secondary winding is inversely proportional to the voltage ratio of the transformer. In other words, if the voltage in the secondary winding is 1/10th of the voltage in the primary winding, then the current in the secondary winding will be 10 times the current in the primary winding.

In this case, the voltage in the secondary winding is 10 V, which is 1/10th of the voltage in the primary winding, which is 100 V. Therefore, the current in the secondary winding will be 10 times the current in the primary winding, which is 2 A. This gives us a current of 20 A in the secondary winding.

Option A is incorrect because it is 50 times the current in the primary winding. Option B is incorrect because it is a time of day. Option C is incorrect because it is a time of day. Option E is incorrect because it is none of the above.