A diode is in series with 220W. If the voltage across the resister is 4V, what is the current through the diode? A. 55 A B. 55.86 A C. 18.2 mA D. 16.3 mA E. None of the above

[amp_mcq option1=”55 A” option2=”55.86 A” option3=”18.2 mA” option4=”16.3 mA E. None of the above” correct=”option3″]

The correct answer is $\boxed{\text{D}}$, 16.3 mA.

The current through a diode is given by Ohm’s law:

$$I = \frac{V}{R}$$

where $I$ is the current in amperes, $V$ is the voltage in volts, and $R$ is the resistance in ohms.

In this case, the voltage across the resistor is 4 V and the resistance is 220 Ω. Therefore, the current through the diode is:

$$I = \frac{4 V}{220 \Omega} = 0.0182 \text{ A} = 16.3 \text{ mA}$$

Option A is incorrect because it is the current through a 220 W resistor, not a diode. Option B is incorrect because it is the current through a 220 Ω resistor, not a diode. Option C is incorrect because it is the current through a 1 Ω resistor, not a diode. Option E is incorrect because it is not one of the possible answers.