Addition of 1101012 and 1011112 is A. 11001002 B. 11010002 C. 11101112 D. 1100112 E. None of the above

The correct answer is $\boxed{\text{C. }11101112}$.

To add two binary numbers, you line them up so that the corresponding digits are in the same column. Then, you add the digits in each column, carrying over any extra digits to the next column.

In this case, we have:

$$\begin{array}{cc}
1 & 1 & 0 & 1 & 0 & 1 \
+ & 1 & 0 & 1 & 1 & 1 \
\hline
1 & 1 & 1 & 0 & 1 & 0 \
\end{array}$$

The answer is $\boxed{\text{C. }11101112}$.

Here is a brief explanation of each option:

• Option A: $11001002$ is incorrect because the sum of the digits in the first column is $1+1+1+1=4$, which is greater than $2$. In binary, when you add two digits that are greater than $2$, you carry over the extra digit to the next column.
• Option B: $11010002$ is incorrect because the sum of the digits in the second column is $0+1+1+1=3$, which is greater than $2$. In binary, when you add two digits that are greater than $2$, you carry over the extra digit to the next column.
• Option C: $11101112$ is correct because the sum of the digits in each column is equal to the corresponding digit in the answer.
• Option D: $1100112$ is incorrect because the sum of the digits in the third column is $1+1+1+1=4$, which is greater than $2$. In binary, when you add two digits that are greater than $2$, you carry over the extra digit to the next column.
• Option E: None of the above is correct because none of the other options are the correct answer.