The correct answer is: E. None of the above
For a type 2 system, the steady-state error for a step input is always non-zero. This is because a type 2 system has a zero-order hold, which means that it cannot track a step input perfectly. The steady-state error for a velocity input is also non-zero, but it is smaller than the steady-state error for a step input. The input for an acceleration input is always zero, because a type 2 system cannot respond to an acceleration input.
Here is a more detailed explanation of each option:
- Option A: The steady-state error for a step input is always zero. This is not true for a type 2 system, as explained above.
- Option B: The steady-state error for a velocity input is always zero. This is also not true for a type 2 system, as explained above.
- Option C: The input for acceleration input is always non-zero. This is true for a type 2 system, as a type 2 system cannot respond to an acceleration input.
- Option D: All of the above. This is not true, as only option C is true for a type 2 system.
- Option E: None of the above. This is the correct answer, as only option C is true for a type 2 system.