For a type 2 system, the steady-state: A. error for a step input is always zero B. error for a velocity input is always zero C. input for acceleration input is always non-zero D. All of the above E. None of the above

error for a step input is always zero
error for a velocity input is always zero
input for acceleration input is always non-zero
All of the above E. None of the above

The correct answer is: E. None of the above

For a type 2 system, the steady-state error for a step input is always non-zero. This is because a type 2 system has a zero-order hold, which means that it cannot track a step input perfectly. The steady-state error for a velocity input is also non-zero, but it is smaller than the steady-state error for a step input. The input for an acceleration input is always zero, because a type 2 system cannot respond to an acceleration input.

Here is a more detailed explanation of each option:

  • Option A: The steady-state error for a step input is always zero. This is not true for a type 2 system, as explained above.
  • Option B: The steady-state error for a velocity input is always zero. This is also not true for a type 2 system, as explained above.
  • Option C: The input for acceleration input is always non-zero. This is true for a type 2 system, as a type 2 system cannot respond to an acceleration input.
  • Option D: All of the above. This is not true, as only option C is true for a type 2 system.
  • Option E: None of the above. This is the correct answer, as only option C is true for a type 2 system.