The correct answer is (b) 1200.
Let $x$ be the number of cars manufactured in the first year. The number of cars manufactured in the second year is $2x$, the number of cars manufactured in the third year is $2^2x=4x$, and the number of cars manufactured in the fourth year is $2^3x=8x$. The average number of cars manufactured in the four years is $750$, so we have
$$\frac{x+2x+4x+8x}{4}=750$$
Solving for $x$, we get $x=250$. Therefore, the number of cars manufactured in the fourth year is $2^3x=2^3(250)=1200$.
Option (a) is incorrect because $1000$ is not a power of $2$. Option (c) is incorrect because $1600$ is not a multiple of $4$. Option (d) is incorrect because $2000$ is not a multiple of $8$.