ASRB NET Exam

Highlights of asrb net Exam 2024

The ASERB NET Exam 2024 is a national-level exam conducted by the https://exam.pscnotes.com/all-india-council-for-technical-Education“>All India Council for Technical Education (AICTE) for the recruitment of Assistant Professors in engineering and technology colleges across India. The exam is held twice a year, in June and December.

The ASERB NET Exam 2024 is a two-stage exam. The first stage is the Preliminary Examination, which is a qualifying exam. The second stage is the Main Examination, which is a descriptive exam.

The Preliminary Examination is a 2-hour exam consisting of 100 multiple choice questions. The questions are based on the following subjects:

The Main Examination is a 3-hour exam consisting of two papers. Paper I is a 100-mark paper on General Aptitude and Engineering Mathematics. Paper II is a 200-mark paper on the subject of specialization.

The ASERB NET Exam 2024 is a very competitive exam. The pass Percentage for the Preliminary Examination is usually around 10%. The pass percentage for the Main Examination is usually around 5%.

The ASERB NET Exam 2024 is a very important exam for those who want to pursue a career in TEACHING in engineering and technology colleges in India. The exam is a good opportunity for those who want to make a difference in the lives of students and help them achieve their dreams.

The ASERB NET Exam 2024 is a challenging exam, but it is not impossible to crack. With proper preparation and hard work, you can achieve success in the exam.

Here are some tips for preparing for the ASERB NET Exam 2024:

I hope these tips will help you prepare for the ASERB NET Exam 2024. Good luck!

The ACRB NET Exam 2024 is a national-level examination conducted by the All India Council for Technical Education (AICTE) for the recruitment of Assistant Professors in various engineering colleges and universities across India. The exam is held twice a year, in June and December.

The highlights of the ACRB NET Exam 2024 are as follows:

The following are some frequently asked questions about the ACRB NET Exam 2024:

  1. What is the syllabus for the ACRB NET Exam 2024?
    The syllabus for the ACRB NET Exam 2024 is prescribed by the AICTE. The syllabus can be downloaded from the official website of the AICTE.

  2. What is the exam pattern for the ACRB NET Exam 2024?
    The exam pattern for the ACRB NET Exam 2024 is as follows:

  3. Paper I will be of 100 marks and will be of two hours duration.

  4. Paper II will be of 150 marks and will be of three hours duration.
  5. The exam will be held in two shifts, morning and evening.
  6. The exam will be conducted in English and Hindi.
  7. The exam will be objective in nature.
  8. The exam will be based on the syllabus prescribed by the AICTE.

  9. What are the eligibility criteria for the ACRB NET Exam 2024?
    The eligibility criteria for the ACRB NET Exam 2024 are as follows:

  10. The candidate must have a Master’s degree in a relevant subject from a recognized university.

  11. The candidate must have a minimum of 55% marks in the Master’s degree examination.
  12. The candidate must have cleared the National Eligibility test (NET) or the State Eligibility Test (SET) conducted by the UGC or any other equivalent test recognized by the AICTE.

  13. What is the application fee for the ACRB NET Exam 2024?
    The application fee for the ACRB NET Exam 2024 is Rs. 1000 for General/OBC candidates and Rs. 500 for SC/ST/PWD candidates.

  14. How to apply for the ACRB NET Exam 2024?
    The application for the ACRB NET Exam 2024 can be submitted online on the official website of the AICTE. The last date to apply for the exam is 30th April 2024.

  15. When will the admit card for the ACRB NET Exam 2024 be available?
    The admit card for the ACRB NET Exam 2024 will be available online on the official website of the AICTE from 15th May 2024.

  16. When will the ACRB NET Exam 2024 be held?
    The ACRB NET Exam 2024 will be held on 10th June 2024.

  17. When will the result of the ACRB NET Exam 2024 be declared?
    The result of the A

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